Canvas exercise transcript — merge, split, move, history
Canvas exercise transcript — merge, split, move, history
Every bin/canvas invocation made while exercising remove, move and history for
Basecamp todo 10330566962. Verbatim command line, exit code, complete stdout and stderr
(not separated — the block holds whatever the invocation printed), appended as each one
was run. Refusals are included, in the order they happened, and none was edited out.
Store: OPENCLAW_WORKSPACE=/Users/lfigea/.openclaw/runs/bc-10330566962-deliver-the-first-priority-canvas-todo-s/canvas-store
Tool: /Users/lfigea/.openclaw/runs/bc-10330566962-deliver-the-first-priority-canvas-todo-s/canvas/bin/canvas
Clone: malkovro/canvas on main at 798ee8c2e3372099646dd2ff044f58b44649bf1d, working tree
clean, nothing edited, nothing committed to it. Every invocation was run from the clone root.
The command line in each heading is the argv, space-joined, with the shell quoting that
delimited each --why removed — the same rendering docs/drive-by-hand/canvas-transcript.md
uses.
python3 bin/canvas create bc-10330566962-merge-and-split-exercise --problem In the 76 invocations behind docs/drive-by-hand/canvas-transcript.md there is no remove, no move, and history was never run once, so nothing in the corpus says what bin/canvas history prints for an id whose node a merge removed. --expected-value This canvas carries a real split and a real merge performed with the four verbs that exist, and the transcript beside it holds the verbatim bin/canvas history output and exit code for the id that survived the split, the id born in it, the id that survived the merge and the stranded id the merge retired.
exit: 0
Canvas-Base: 96c0e3d216f5039058b68930320ed1c0da238730
Canvas-File: /Users/lfigea/.openclaw/runs/bc-10330566962-deliver-the-first-priority-canvas-todo-s/canvas-store/state/canvas/bc-10330566962-merge-and-split-exercise.xml
python3 bin/canvas read bc-10330566962-merge-and-split-exercise
exit: 0
Canvas-Base: 96c0e3d216f5039058b68930320ed1c0da238730
<?xml version="1.0" encoding="UTF-8"?>
<canvas ledger="bc-10330566962-merge-and-split-exercise" schema="1">
<text id="qvwb" v="1">In the 76 invocations behind docs/drive-by-hand/canvas-transcript.md there is no remove, no move, and history was never run once, so nothing in the corpus says what bin/canvas history prints for an id whose node a merge removed.</text>
<text id="g4fe" v="1">This canvas carries a real split and a real merge performed with the four verbs that exist, and the transcript beside it holds the verbatim bin/canvas history output and exit code for the id that survived the split, the id born in it, the id that survived the merge and the stranded id the merge retired.</text>
</canvas>
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --into root --type section --title What a merge costs today --why Holds the two halves of the merge claim that node-identity.md:445-446 makes, so the pair sits inside one container a reader can ask about rather than as loose siblings of the problem statement. It is a container and holds no text of its own; what would make it unnecessary is the merge claim turning out to be one sentence rather than two joinable ones. --base 96c0e3d216f5039058b68930320ed1c0da238730
exit: 0
Canvas-Node: xkq2
Canvas-Base: a7ac6eaab692d089dd2a1de5bf3fc54480ae181d
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --into xkq2 --type text --text A merge is a replace plus a remove, so one node's reasons survive on the id that stays in the document. --why States the surviving half of the merge cost, quoting node-identity.md:445. It is the half that is not a loss, and it is separated from the half that is so that the exercise has two adjacent nodes whose content genuinely joins into one sentence. It would be wrong if a merge stopped being expressible as replace plus remove. --base a7ac6eaab692d089dd2a1de5bf3fc54480ae181d
exit: 0
Canvas-Node: oskz
Canvas-Base: 02265a7565035e7e77f25de085cf496bcba4a7b2
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --after oskz --type text --text The other node's reasons dead-end at a retired id that the surviving node does not point at. --why States the losing half of the same merge cost, quoting node-identity.md:446. Node oskz gives the clause about the id that survives; this one differs in that it is about the id that does not, and it is the only node here that asserts the absence of a pointer, which is the thing the history run in this exercise has to check. Retiring oskz would not retire this. --base 02265a7565035e7e77f25de085cf496bcba4a7b2
exit: 0
Canvas-Node: dwqu
Canvas-Base: f05035c60e48dcfdab36631acad1b29acc13aa29
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --after dwqu --type text --text A split is a replace plus an insert, so one half keeps the original id and every reason ever written for it. The other half is born at v=1 with an empty history, and nothing the tool writes records where its content came from. --why Carries the split cost from node-identity.md:443-444 as one node deliberately holding two sentences, so the exercise has a node whose content can be cut in half with a replace and an insert. It differs from oskz and dwqu, which are about merge, and unlike either of them it is the node this exercise will split. It would be wrong if a split stopped being replace plus insert. --base f05035c60e48dcfdab36631acad1b29acc13aa29
exit: 0
Canvas-Node: e8ec
Canvas-Base: 3a0736827b6390aeb2062c364a536a18444d3a3e
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --after e8ec --type text --text node-identity.md:453-454 says neither option for merge lineage is decided there and that neither should be decided by whoever happens to write replace first. --why Records the constraint the open item puts on the decision procedure rather than on the answer, citing node-identity.md:453-454. It is the one node in section xkq2 that is about who may decide rather than about what a verb costs, and this exercise will leave it untouched so that history on an edited id can be read against history on one that was only ever inserted. --base 3a0736827b6390aeb2062c364a536a18444d3a3e
exit: 0
Canvas-Node: ffra
Canvas-Base: be176426f11f1bea8f4be8971914ba1b8ac69b95
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --into root --type section --title Whether a restructure may ever be atomic --why Holds the second open item, node-identity.md:455-459, apart from the merge material in section xkq2: that section is about what a merge costs a node's history, this one is about whether a sequence of edits may be grouped at all, and the two are ruled on separately by the todo. It is a container and holds no text of its own; it would be unnecessary if the second open item collapsed into the first. --base be176426f11f1bea8f4be8971914ba1b8ac69b95
exit: 0
Canvas-Node: sdtf
Canvas-Base: df551a23f4d8542d050cc5e807c8c882577e2542
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --into sdtf --type text --text A grouping mechanism would have to be one that is not a multi-node write, because store.py refuses any write where more than the node named in the Canvas-Node trailer differs, for every caller and every import path. --why Gives section sdtf the constraint any yes to the atomic question would have to clear, citing node-identity.md:349-362. It is the only node in the canvas that names the store's identity guard rather than a verb's cost, and it will be the sole child that makes sdtf a populated container when this exercise moves it. It would be wrong if the guard moved out of the write path to the command line. --base df551a23f4d8542d050cc5e807c8c882577e2542
exit: 0
Canvas-Node: ps58
Canvas-Base: b1b52337b8eb297d279e34830d028f6e7932c142
python3 bin/canvas read bc-10330566962-merge-and-split-exercise
(the document as built, before any split, merge or move)
exit: 0
Canvas-Base: b1b52337b8eb297d279e34830d028f6e7932c142
<?xml version="1.0" encoding="UTF-8"?>
<canvas ledger="bc-10330566962-merge-and-split-exercise" schema="1">
<text id="qvwb" v="1">In the 76 invocations behind docs/drive-by-hand/canvas-transcript.md there is no remove, no move, and history was never run once, so nothing in the corpus says what bin/canvas history prints for an id whose node a merge removed.</text>
<text id="g4fe" v="1">This canvas carries a real split and a real merge performed with the four verbs that exist, and the transcript beside it holds the verbatim bin/canvas history output and exit code for the id that survived the split, the id born in it, the id that survived the merge and the stranded id the merge retired.</text>
<section id="xkq2" v="1" title="What a merge costs today">
<text id="oskz" v="1">A merge is a replace plus a remove, so one node's reasons survive on the id that stays in the document.</text>
<text id="dwqu" v="1">The other node's reasons dead-end at a retired id that the surviving node does not point at.</text>
<text id="e8ec" v="1">A split is a replace plus an insert, so one half keeps the original id and every reason ever written for it. The other half is born at v=1 with an empty history, and nothing the tool writes records where its content came from.</text>
<text id="ffra" v="1">node-identity.md:453-454 says neither option for merge lineage is decided there and that neither should be decided by whoever happens to write replace first.</text>
</section>
<section id="sdtf" v="1" title="Whether a restructure may ever be atomic">
<text id="ps58" v="1">A grouping mechanism would have to be one that is not a multi-node write, because store.py refuses any write where more than the node named in the Canvas-Node trailer differs, for every caller and every import path.</text>
</section>
</canvas>
python3 bin/canvas replace bc-10330566962-merge-and-split-exercise e8ec --text A split is a replace plus an insert, so one half keeps the original id and every reason ever written for it. --why Cuts this node down to the half of the split cost that is about the id that survives, node-identity.md:443. The second sentence it held is about the half that is born instead, which is a different claim with a different thing that would falsify it, and it is going into its own node in the same insert-sized step the tool requires. It would be wrong if keeping the original id stopped being what a replace does. --base b1b52337b8eb297d279e34830d028f6e7932c142
(the split, half one: the original node cut down to its first idea)
exit: 0
Canvas-Node: e8ec
Canvas-Base: bacf86fe215abc231cf5be3d39d50742bbabb600
python3 bin/canvas insert bc-10330566962-merge-and-split-exercise --after e8ec --type text --text The other half is born at v=1 with an empty history, and nothing the tool writes records where its content came from. --why Holds the half of the split cost that node e8ec no longer states: e8ec now carries only the claim about the id that survives a split, and this node carries the claim about the id that is born in one, which node-identity.md:443-444 states as a separate consequence. This content was the second sentence of e8ec until the replace one commit earlier. It would be retired if a born node ever did carry its origin, which would leave e8ec's half standing. --base bacf86fe215abc231cf5be3d39d50742bbabb600
(the split, half two: the other idea, born as its own node)
exit: 0
Canvas-Node: dkjk
Canvas-Base: e9f2b033e48b95bd2bdb0e116b253ab84e876de2
python3 bin/canvas replace bc-10330566962-merge-and-split-exercise oskz --text A merge is a replace plus a remove, so one node's reasons survive on the id that stays in the document, and the other node's reasons dead-end at a retired id that the surviving node does not point at. --why Takes on the clause about the id that does not survive, so that node-identity.md:445-446 reads here as the one consequence it is rather than as two fragments a reader has to associate by adjacency. Node dwqu holds that clause today and will hold nothing this node does not once this commit lands. It would be wrong if a merge stopped costing the losing id its pointer. --base e9f2b033e48b95bd2bdb0e116b253ab84e876de2
(the merge, half one: the surviving node takes on both clauses)
exit: 0
Canvas-Node: oskz
Canvas-Base: cdf439a48b1deded024ce879ef2048460133f0d4
python3 bin/canvas remove bc-10330566962-merge-and-split-exercise dwqu --why Merged upward; reason as above. --base cdf439a48b1deded024ce879ef2048460133f0d4
(the merge, half two, first attempt: the reason a writer reaches for when the remove’s justification is the replace’s — the bare back-reference VERDICT.md 5.2 refuses)
exit: 2
canvas: --why must say what this node is for, not where it sits; if the reason is another node's, name that node's id and say what differs here.
Canvas-Node: dwqu
Canvas-About: option --why
Canvas-About: ledger id bc-10330566962-merge-and-split-exercise
Canvas-Next: re-run the same command with a --why that says what this node holds that the one you were pointing at does not — and if the reason really is that other node's, name its four-character id in the reason and say what differs here; nothing was written, committed or minted
Canvas-Exit: 2 — the tool or its environment is wrong; do not touch the canvas
python3 bin/canvas remove bc-10330566962-merge-and-split-exercise dwqu --why The one clause this node holds — that the losing id's reasons dead-end at a retired id the survivor does not point at — now stands word for word inside node oskz, so keeping it would leave the canvas asserting the same thing twice with two ids a reader would have to reconcile. What oskz does not take over is this id's own history, which stays reachable only by asking for this id by name; that is the cost node-identity.md:446 names and this exercise is here to show. It would have been wrong to remove this node while any part of its clause was still only here. --base cdf439a48b1deded024ce879ef2048460133f0d4
(the merge, half two, second attempt: a reason for deleting this particular node rather than for the operation it was part of)
exit: 0
Canvas-Node: dwqu
Canvas-Base: ce80ed3bb301f01e1f4864edf58a7b6a60ed0aa2
python3 bin/canvas move bc-10330566962-merge-and-split-exercise sdtf --after g4fe --why Puts the question of whether a restructure may be grouped at all ahead of the section that prices what one costs, because node-identity.md:433-459 leaves the two as independent items and a reader who meets the merge section first reads the atomic question as a consequence of merge lineage rather than as its own ruling. Only the position changes: this section keeps its id and carries its child ps58 with it. It would be wrong if the second open item ever turned out to depend on how the first is answered. --base ce80ed3bb301f01e1f4864edf58a7b6a60ed0aa2
(move on a populated container: section sdtf holds one child, ps58)
exit: 0
Canvas-Node: sdtf
Canvas-Base: 701a6736e58bde4a8c2938e971d88508d2519fed
python3 bin/canvas history bc-10330566962-merge-and-split-exercise e8ec
(the id that SURVIVED the split)
exit: 0
Canvas-Node: e8ec
Canvas-Commit: 3a0736827b6390aeb2062c364a536a18444d3a3e
Canvas-Author: lfigea | by-hand
insert: Carries the split cost from node-identity.md:443-444 as one node deliberately holding two sentences, so the exercise has a node whose content can be cut in half with a replace and an insert. It differs from oskz and dwqu, which are about merge, and unlike either of them it is the node this exercise will split. It would be wrong if a split stopped being replace plus insert.
Canvas-Commit: bacf86fe215abc231cf5be3d39d50742bbabb600
Canvas-Author: lfigea | by-hand
replace: Cuts this node down to the half of the split cost that is about the id that survives, node-identity.md:443. The second sentence it held is about the half that is born instead, which is a different claim with a different thing that would falsify it, and it is going into its own node in the same insert-sized step the tool requires. It would be wrong if keeping the original id stopped being what a replace does.
python3 bin/canvas history bc-10330566962-merge-and-split-exercise dkjk
(the id that was BORN in the split)
exit: 0
Canvas-Node: dkjk
Canvas-Commit: e9f2b033e48b95bd2bdb0e116b253ab84e876de2
Canvas-Author: lfigea | by-hand
insert: Holds the half of the split cost that node e8ec no longer states: e8ec now carries only the claim about the id that survives a split, and this node carries the claim about the id that is born in one, which node-identity.md:443-444 states as a separate consequence. This content was the second sentence of e8ec until the replace one commit earlier. It would be retired if a born node ever did carry its origin, which would leave e8ec's half standing.
python3 bin/canvas history bc-10330566962-merge-and-split-exercise oskz
(the id that SURVIVED the merge)
exit: 0
Canvas-Node: oskz
Canvas-Commit: 02265a7565035e7e77f25de085cf496bcba4a7b2
Canvas-Author: lfigea | by-hand
insert: States the surviving half of the merge cost, quoting node-identity.md:445. It is the half that is not a loss, and it is separated from the half that is so that the exercise has two adjacent nodes whose content genuinely joins into one sentence. It would be wrong if a merge stopped being expressible as replace plus remove.
Canvas-Commit: cdf439a48b1deded024ce879ef2048460133f0d4
Canvas-Author: lfigea | by-hand
replace: Takes on the clause about the id that does not survive, so that node-identity.md:445-446 reads here as the one consequence it is rather than as two fragments a reader has to associate by adjacency. Node dwqu holds that clause today and will hold nothing this node does not once this commit lands. It would be wrong if a merge stopped costing the losing id its pointer.
python3 bin/canvas history bc-10330566962-merge-and-split-exercise dwqu
(the STRANDED id the merge retired — the node is gone from the document)
exit: 0
Canvas-Node: dwqu
Canvas-Commit: f05035c60e48dcfdab36631acad1b29acc13aa29
Canvas-Author: lfigea | by-hand
insert: States the losing half of the same merge cost, quoting node-identity.md:446. Node oskz gives the clause about the id that survives; this one differs in that it is about the id that does not, and it is the only node here that asserts the absence of a pointer, which is the thing the history run in this exercise has to check. Retiring oskz would not retire this.
Canvas-Commit: ce80ed3bb301f01e1f4864edf58a7b6a60ed0aa2
Canvas-Author: lfigea | by-hand
remove: The one clause this node holds — that the losing id's reasons dead-end at a retired id the survivor does not point at — now stands word for word inside node oskz, so keeping it would leave the canvas asserting the same thing twice with two ids a reader would have to reconcile. What oskz does not take over is this id's own history, which stays reachable only by asking for this id by name; that is the cost node-identity.md:446 names and this exercise is here to show. It would have been wrong to remove this node while any part of its clause was still only here.
python3 bin/canvas history bc-10330566962-merge-and-split-exercise sdtf
(the moved container: one query spans the move, and the child it carried is not named)
exit: 0
Canvas-Node: sdtf
Canvas-Commit: df551a23f4d8542d050cc5e807c8c882577e2542
Canvas-Author: lfigea | by-hand
insert: Holds the second open item, node-identity.md:455-459, apart from the merge material in section xkq2: that section is about what a merge costs a node's history, this one is about whether a sequence of edits may be grouped at all, and the two are ruled on separately by the todo. It is a container and holds no text of its own; it would be unnecessary if the second open item collapsed into the first.
Canvas-Commit: 701a6736e58bde4a8c2938e971d88508d2519fed
Canvas-Author: lfigea | by-hand
move: Puts the question of whether a restructure may be grouped at all ahead of the section that prices what one costs, because node-identity.md:433-459 leaves the two as independent items and a reader who meets the merge section first reads the atomic question as a consequence of merge lineage rather than as its own ruling. Only the position changes: this section keeps its id and carries its child ps58 with it. It would be wrong if the second open item ever turned out to depend on how the first is answered.
python3 bin/canvas history bc-10330566962-merge-and-split-exercise ps58
(the child the move carried: no commit names it for the move)
exit: 0
Canvas-Node: ps58
Canvas-Commit: b1b52337b8eb297d279e34830d028f6e7932c142
Canvas-Author: lfigea | by-hand
insert: Gives section sdtf the constraint any yes to the atomic question would have to clear, citing node-identity.md:349-362. It is the only node in the canvas that names the store's identity guard rather than a verb's cost, and it will be the sole child that makes sdtf a populated container when this exercise moves it. It would be wrong if the guard moved out of the write path to the command line.
python3 bin/canvas history bc-10330566962-merge-and-split-exercise ffra
(an untouched node, for contrast: inserted once and never edited)
exit: 0
Canvas-Node: ffra
Canvas-Commit: be176426f11f1bea8f4be8971914ba1b8ac69b95
Canvas-Author: lfigea | by-hand
insert: Records the constraint the open item puts on the decision procedure rather than on the answer, citing node-identity.md:453-454. It is the one node in section xkq2 that is about who may decide rather than about what a verb costs, and this exercise will leave it untouched so that history on an edited id can be read against history on one that was only ever inserted.
python3 bin/canvas history bc-10330566962-merge-and-split-exercise root
(the root, asked for by the name the position flags use)
exit: 1
canvas: no node with id root in the history of the canvas for bc-10330566962-merge-and-split-exercise: no commit names it, so it was never a node of this canvas. The canvas is there; the node is not
Canvas-Node: root
Canvas-About: ledger id bc-10330566962-merge-and-split-exercise
Canvas-About: canvas /Users/lfigea/.openclaw/runs/bc-10330566962-deliver-the-first-priority-canvas-todo-s/canvas-store/state/canvas/bc-10330566962-merge-and-split-exercise.xml
Canvas-Next: `bin/canvas read bc-10330566962-merge-and-split-exercise` prints the canvas and every id in it; ask one of those for its history
Canvas-Exit: 1 — the request is wrong against the store as it stands; re-read and re-decide
python3 bin/canvas read bc-10330566962-merge-and-split-exercise
(the final document, after the split, the merge and the move)
exit: 0
Canvas-Base: 701a6736e58bde4a8c2938e971d88508d2519fed
<?xml version="1.0" encoding="UTF-8"?>
<canvas ledger="bc-10330566962-merge-and-split-exercise" schema="1">
<text id="qvwb" v="1">In the 76 invocations behind docs/drive-by-hand/canvas-transcript.md there is no remove, no move, and history was never run once, so nothing in the corpus says what bin/canvas history prints for an id whose node a merge removed.</text>
<text id="g4fe" v="1">This canvas carries a real split and a real merge performed with the four verbs that exist, and the transcript beside it holds the verbatim bin/canvas history output and exit code for the id that survived the split, the id born in it, the id that survived the merge and the stranded id the merge retired.</text>
<section id="sdtf" v="2" title="Whether a restructure may ever be atomic">
<text id="ps58" v="1">A grouping mechanism would have to be one that is not a multi-node write, because store.py refuses any write where more than the node named in the Canvas-Node trailer differs, for every caller and every import path.</text>
</section>
<section id="xkq2" v="1" title="What a merge costs today">
<text id="oskz" v="2">A merge is a replace plus a remove, so one node's reasons survive on the id that stays in the document, and the other node's reasons dead-end at a retired id that the surviving node does not point at.</text>
<text id="e8ec" v="2">A split is a replace plus an insert, so one half keeps the original id and every reason ever written for it.</text>
<text id="dkjk" v="1">The other half is born at v=1 with an empty history, and nothing the tool writes records where its content came from.</text>
<text id="ffra" v="1">node-identity.md:453-454 says neither option for merge lineage is decided there and that neither should be decided by whoever happens to write replace first.</text>
</section>
</canvas>
Appendix — two checks on the store that are not bin/canvas invocations
Recorded here because FINDINGS.md cites them. Both were run in
/Users/lfigea/.openclaw/runs/bc-10330566962-deliver-the-first-priority-canvas-todo-s/canvas-store/state/canvas,
which is the git repository the store keeps.
git log --oneline | wc -l
exit: 0
15
Fifteen commits for twenty-five invocations: three from create (the root alone, then the
problem, then the expected value), then the twelve writes that succeeded — eight insert, two
replace, one remove, one move — and nothing at all for the remove that was refused at
exit 2. The three reads and the eight history runs write nothing, and the refusal wrote no
commit.
git log --format='%h %s' --grep='^Canvas-Node: dwqu$'
exit: 0
ce80ed3 remove dwqu: The one clause this node holds — that the losing id's reasons dead-end at a retired id the survivor does not point at — now stands word for word inside node oskz, so keeping it would leave the canvas asserting the same thing twice with two ids a reader would have to reconcile. What oskz does not take over is this id's own history, which stays reachable only by asking for this id by name; that is the cost node-identity.md:446 names and this exercise is here to show. It would have been wrong to remove this node while any part of its clause was still only here.
f05035c insert dwqu: States the losing half of the same merge cost, quoting node-identity.md:446. Node oskz gives the clause about the id that survives; this one differs in that it is about the id that does not, and it is the only node here that asserts the absence of a pointer, which is the thing the history run in this exercise has to check. Retiring oskz would not retire this.
Two commits name the retired id, and they are exactly the two entries
bin/canvas history … dwqu printed. The reason is in the commit subject; the trailers on
that commit are Canvas-Node: dwqu, Canvas-Author: and Canvas-Base: and nothing else —
there is no trailer naming oskz.